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## Chapter 2 Fractions and Decimals Exercise 2.6

Question 1: Find:
(i) 0.2 × 6
= 2/10 × 6
= 12/10
= 1.2

(ii) 8 × 4.6

= 8 × 46/10
= 368/10
= 36.8

(iii) 2.71 × 5

= 271/100 × 5
= 1355/100
= 13.55

(iv) 20.1 × 4

= 201/10 × 4
= 804/10
= 80.4

(v) 0.05 × 7

= 5/100 × 7
= 35/100
= 0.35

(vi) 211.02 × 4

= 21102/100 × 4
= 84408/100
= 844.08

(vii) 2 × 0.86

= 2 × 86/100
= 172/100
= 1.72

Question 2: Find the area of rectangle whose length is 5.7cm and breadth is 3 cm.

Length of the rectangle = 5.7 cm
Breadth of the rectangle = 3 cm
Area of the rectangle = length × breadth
= 5.7 × 3
= 17.1 cm2

Question 3: Find:
(i) 1.3 × 10

= 1.3 × 10 = 13

(ii) 36.8 × 10

= 36.8 × 10 = 368

(iii) 153.7 × 10

= 153.7 × 10 = 1537

(iv) 168.07 × 10

= 168.07 × 10 = 1680.7

(v) 31.1 × 100

= 31.1 × 100 = 3110

(vi) 156.1 × 100

= 156.1 × 100 = 15610

(vii) 3.62 × 100

= 3.62 × 100 = 362

(viii) 43.07 × 100

= 43.07 × 100 = 4307

(ix) 0.5 × 10

= 0.5 × 10 = 5

(x) 0.08 × 10

= 0.08 × 10 = 0.8

(xi) 0.9 × 100

= 0.9 × 100 = 90

(xii) 0.03 × 1000

= 0.03 × 1000 = 30

Question 4: A two-wheeler covers a distance of 55.3 km in one litre of petrol. How much distance will it cover in 10 litres of petrol?

Distance covered by two-wheeler in 1 litre of petrol = 55.3 km
Distance covered by two wheeler in 10 litre of petrol = ?
= 10 × 55.3
= 553 km
Therefore, two-wheeler covers a distance in 10L of petrol is 553 km.

Question 5: Find:
(i) 2.5 × 0.3

= 25/10 × 3/10
= 75/100
= 0.75

(ii) 0.1 × 51.7

= 1/10 × 517/10
= 517/100
= 5.17

(iii) 0.2 × 316.8

= 2/10 × 3168/10
= 6336/100
= 63.36

(iv) 1.3 × 3.1

= 13/10 × 31/10
= 403/100
= 4.03

(v) 0.5 × 0.05

= 5/10 × 5/100
= 25/1000
= 0.025

(vi) 11.2 × 0.15

= 112/10 × 15/100
= 1680/1000
= 1.680

(vii) 1.07 × 0.02

= 107/100 × 2/100
= 214/10000
= 0.0214

(viii) 10.05 × 1.05

= 1005/100 × 105/100
= 105525/10000
= 10.5525

(ix) 101.01 × 0.01

= 10101/100 × 1/100
= 10101/10000
= 1.0101

(x) 100.01 × 1.1