Chapter 2 Whole Numbers Exercise 2.2
Question 1: Find the sum by suitable rearrangement:a) 837 + 208 + 363
b) 1962 + 453 + 1538 + 647
Answer:
a)
= 837 + 208 + 363
= (837 + 363) + 208
= 1200 + 208
= 1408
b)
= 1962 + 453 + 1538 + 647
= (1962 + 1538) + (453 + 647)
= 3500 + 1100
= 4600
Question 2: Find the product by suitable rearrangement:
a) 2 × 1768 × 50
b) 4 × 166 × 25
c) 8 × 291 × 125
d) 625 × 279 × 16
e) 285 × 5 × 60
f) 125 × 40 × 8 × 25
Answer:
a)
= 2 × 1768 × 50
= (2 × 50) × 1768
= 100 × 1768
= 176800
b)
= 4 × 166 × 25
= (4 × 25) × 166
= 100 × 166
= 16600
c)
= 8 × 291 × 125
= (8 × 125) × 291
= 1000 × 291
= 291000
d)
= 625 × 279 × 16
= (625 × 16) × 279
= 10000 × 279
= 2790000
e)
= 285 × 5 × 60
= 285 × (60 × 5)
= 285 × 300
= 85500
f)
125 × 40 × 8 × 25
= (125 × 8) × (40 × 25)
= 1000 × 1000
= 1000000
Question 3: Find the value of the following:
a) 297 × 17 + 297 × 3
b) 54279 × 92 + 8 × 54279
c) 81265 × 169 - 81265 × 69
d) 3845 × 5 × 782 + 769 × 25 × 218
Answer:
a)
= 297 × 17 + 297 × 3
= 297 × (17 + 3)
= 297 × 20
= 5940
b)
= 54279 × 92 + 8 × 54279
= 54279 × 92 + 54279 × 8
= 54279 × (92 + 8)
= 54279 × 100
= 5427900
c)
= 81265 × 169 - 81265 × 69
= 81265 × (169 - 69)
= 81265 × 100
= 8126500
d)
= 3845 × 5 × 782 + 769 × 25 × 218
= 3845 × 5 × 782 + 769 × 5 × 5 × 218
= 3845 × 5 × 782 + 3845 × 5 × 218
= 3845 × 5 × (782 + 218)
= 19225 × 1000
= 19225000
Question 4: Find the product using suitable properties.
a) 738 × 103
b) 854 × 102
c) 258 × 1008
d) 1005 × 168
Answer:
a)
= 738 × 103
= 738 × (100 + 3)
= 738 × 100 + 738 × 3 (distributive property)
= 73800 + 2214
= 76014
b)
= 854 × 102
= 854 × (100 + 2)
= 854 × 100 + 854 × 2 (distributive property)
= 85400 + 1708
= 87108
c)
= 258 × 1008
= 258 × (1000 + 8)
= 258 × 1000 + 258 × 8 (distributive property)
= 258000 + 2064
= 260064
d)
= 1005 × 168
= (1000 + 5) × 168
= 1000 × 168 + 5 × 168 (distributive property)
= 168000 + 840
= 168840
Question 5: A taxi driver filled his car petrol tank with 40 litres of petrol on Monday. The next day, he filled the tank with 50 litres of petrol. If the petrol costs ₹44 per litre, how much did he spend in all on petrol?
Answer:
Petrol filled on Monday = 40 litres
Petrol filled on Tuesday = 50 litres
Total petrol filled = 40 + 50 = 90 litres
Cost of petrol per litre = ₹ 44
Total money spent = ?
= 44 × 90
= ₹3960
Therefore, the taxi driver spent ₹3960 on petrol for 2 days i.e. Monday and Tuesday.
Question 6: A vendor supplies 32 litres of milk to a hotel in the morning and 68 litres of milk in the evening. If the milk costs ₹45 per litre, how much money is due to the vendor per day?
Answer:
Milk supplied in the morning = 32 litres
Milk supplied in the evening = 68 litres
Total milk supplied in the day = 32 + 68 = 100 litres
Cost of milk per litre = ₹ 45
Total cost of milk per day = ?
= 45 × 100
= ₹ 4500
Therefore, the money is due to the vendor per day is ₹ 4500
Question 7: Match the following:
i) 425 × 136 = 425 × (6 + 30 + 100) a) Commutativity under multiplication.
ii) 2 × 49 × 50 = 2 × 50 × 49 b) Commutativity under addition.
iii) 80 + 2005 + 20 = 80 + 20 + 2005 c) Distributivity of multiplication over addition.
Answer:
i) 425 × 136 = 425 × (6 + 30 + 100) - c) Distributivity of multiplication over addition.
ii) 2 × 49 × 50 = 2 × 50 × 49 - a) Commutativity under multiplication.
iii) 80 + 2005 + 20 = 80 + 20 + 2005 - b) Commutativity under addition.
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